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What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10 24 kg and radius of the earth is 6.4 × 10 6 m)

Question

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 × 10 24 kg and radius of the earth is 6.4 × 10 6 m)

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Solution

The gravitational force between two objects can be calculated using Newton's law of universal gravitation. The formula is:

F = G * (m1 * m2) / r^2

where:

  • F is the force between the masses,
  • G is the gravitational constant,
  • m1 is the first mass,
  • m2 is the second mass,
  • r is the distance between the centers of the two masses.

In this case, m1 is the mass of the Earth, which is 6 × 10^24 kg, m2 is the mass of the object, which is 1 kg, and r is the radius of the Earth, which is 6.4 × 10^6 m. The gravitational constant G is approximately 6.674 × 10^-11 N(m/kg)^2.

Substituting these values into the formula gives:

F = 6.674 × 10^-11 * (6 × 10^24 * 1) / (6.4 × 10^6)^2

Solving this equation gives the magnitude of the gravitational force between the Earth and the 1 kg object on its surface, which is approximately 9.8 N.

This problem has been solved

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