calculate the position of the final image in the astronomical telescope with the data of step P5. Estimate the position of the first image, realizing that the object is very far away. Then, use the Thin-Lens Formula to calculate the position of the final image from the second lens.

The distance between the two lenses in an astronomical telescope is 157 cm. It has a magnification of -44.0 .(a) Determine the focal length of the eyepiece. (b) Determine the focal length of the objective.

An object is placed 12 cm in front of a lens with a focal length of 8.0 cm.(i) (2 marks)Calculate the image distance.(ii) (2 marks)Sketch a ray diagram of the image, and lens, showing at least the three principal rays. You may include more relevant rays if you wish.

A 5mm high pin is placed at a distance of 15cm from a convex lens of focal length 10cm. A second lens of focal length 5cm is placed 40cm from the first lens and 55cm from the pin. Find (a) the position of the final image, (b) its nature and (c) its size.

An object placed in front of a lens, forms a virtual image whose magnifications is 0.5. The focal length of the lens is 30cm. Calculate the object distance.(with sign)

To determine the calculated image distance, we used the formula 𝑑𝑖=𝑑𝑜⋅𝑓1𝑑𝑜−𝑓1d i​ = d o​ −f 1​ d o​ ⋅f 1​ ​ . For the image distance after the second lens, a similar formula was applied, but instead of using the object distance directly, we used the difference between the distance from the first lens and the location of the image formed by the first lens as the effective object distance. This was expressed as 𝑑𝑜′=𝑑𝑙𝑒𝑛𝑠−𝑑𝑖d o′​ =d lens​ −d i​ . We also computed the magnification for each lens using both theoretical predictions and experimental data. The theoretical magnification was calculated by dividing the image distance by the object distance. This process was applied to both lenses, with the image formed by the first lens serving as the object for the second lens in our calculations.