The average of twelve positive numbers is 15. If the average of the first four numbers is 9 and that of the last four numbers is 26. What is the average of the remaining four numbers?Options1260101525
Question
The average of twelve positive numbers is 15. If the average of the first four numbers is 9 and that of the last four numbers is 26. What is the average of the remaining four numbers?Options1260101525
Solution
To solve this problem, we first need to understand that the average of a set of numbers is the sum of those numbers divided by the quantity of numbers.
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The average of twelve numbers is 15, so the sum of these twelve numbers is 15 * 12 = 180.
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The average of the first four numbers is 9, so the sum of these four numbers is 9 * 4 = 36.
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The average of the last four numbers is 26, so the sum of these four numbers is 26 * 4 = 104.
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To find the sum of the remaining four numbers, we subtract the sum of the first four numbers and the last four numbers from the total sum. So, 180 - 36 - 104 = 40.
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Finally, to find the average of these remaining four numbers, we divide the sum by the quantity of numbers. So, 40 / 4 = 10.
Therefore, the average of the remaining four numbers is 10.
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