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If the moment of inertia of a section about its axis is I and its effective sectional area is A, its radius of gyration r about the axis, isa.r=I^2/Ab.r=(I/A)^2c.r=I/Ad.r=(I/A)^0.5Clear my choice

Question

If the moment of inertia of a section about its axis is I and its effective sectional area is A, its radius of gyration r about the axis, isa.r=I^2/Ab.r=(I/A)^2c.r=I/Ad.r=(I/A)^0.5Clear my choice

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Solution

The radius of gyration (r) of a section about its axis is defined as the square root of the ratio of the moment of inertia (I) to the area (A). Therefore, the correct answer is:

d. r = (I/A)^0.5

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