Knowee
Questions
Features
Study Tools

Analyze the following code. Please select all that apply. public class A extends B { } class B {   public B(String s) {   } } Group of answer choicesThe program has a compile error because A does not have a default constructor.The program has a compile error because the default constructor of A invokes the default constructor of B, but B does not have a default constructor.The program would compile fine if you add the following constructor into A: A(String s) { }The program would compile fine if you add the following constructor into A: A(String s) { super(s); }

Question

Analyze the following code. Please select all that apply. public class A extends B { } class B {   public B(String s) {   } } Group of answer choicesThe program has a compile error because A does not have a default constructor.The program has a compile error because the default constructor of A invokes the default constructor of B, but B does not have a default constructor.The program would compile fine if you add the following constructor into A: A(String s) { }The program would compile fine if you add the following constructor into A: A(String s) { super(s); }

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The program has a compile error because the default constructor of A invokes the default constructor of B, but B does not have a default constructor.

The program would compile fine if you add the following constructor into A: A(String s) { super(s); }

These two statements are correct. In Java, when you create a subclass (A) from a superclass (B), the default constructor of the subclass (A) will try to call the default constructor of the superclass (B). If the superclass (B) does not have a default constructor (a constructor with no parameters), then a compile error will occur.

To fix this, you can add a constructor to the subclass (A) that calls the superclass's (B) constructor with a parameter, like this: A(String s) { super(s); }. This way, when you create an object of the subclass (A), it will use this constructor and pass the parameter to the superclass's (B) constructor.

This problem has been solved

Similar Questions

Analyze the following code:  _____public class A extends B {}class B {  public B(String s) {  }}A. The program has a compile error because A does not have a default constructor.B. The program has a compile error because the default constructor of A invokes the default constructor of B, but B does not have a default constructor.C. The program would compile fine if you add the following constructor into A: A(String s) { }D. The program would compile fine if you add the following constructor into A: A(String s) { super(s); }

Analyze the following code. Please select all that apply from the options below.  public class Test {   public static void main(String[] args) {     A a = new A();     a.print();   } }  class A {   String s;    A(String s) {     this.s = s;   }    void print() {     System.out.println(s);   } } Group of answer choicesThe program has a compile error because class A is not a public class.The program has a compile error because class A does not have a default constructor.The program compiles and runs fine and prints nothing.The program would compile and run if you change A a = new A() to A a = new A("5")

Analyze the following code and choose two correct statements from below. public class Test extends A {    public static void main(String[] args) {     Test t = new Test();     t.print();   } } class A {   String s;   A(String s) {     this.s = s;      }   public void print() {     System.out.println(s);   } } Group of answer choicesThe program does not compile because Test does not have a default constructor Test().The program has an implicit default constructor Test(), but it cannot be compiled, because its super class does not have a default constructor. The program would compile if the constructor in the class A were removed.The program would compile if a default constructor A(){ } is added to class A explicitly.The program compiles, but it has a runtime error due to the conflict on the method name print.

Analyze the following code carefully. Choose a statement from the options below.   class TempClass {   int i;   public void TempClass(int j) {     int i = j;    } } public class C { public static void main(String[] args) {     TempClass temp = new TempClass(2);   } } Group of answer choicesThe program has a compile error because TempClass does not have a default constructor.The program has a compile error because TempClass does not have a constructor with an int argument.The program compiles fine, but it does not run because class C is not public.The program compiles and runs fine.

Analyze the following code and choose a correct answer from below. public class Test {    public static void main(String[] args) {     B b = new B();     b.m(5);     System.out.println("i is " + b.i);   } } class A {   int i;   public void m(int i) {      this.i = i;    } }  class B extends A {   public void m(String s) {   } } Group of answer choicesThe program has a compile error, because m is overridden with a different signature in B.The program has a compile error, because b.m(5) cannot be invoked since the method m(int) is hidden in B.The program has a runtime error on b.i, because i is not accessible from b.The method m is not overridden in B. B inherits the method m from A and defines an overloaded method m in B.

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.