Question 14A random sample of 61 Basic Statistics students were asked what they thought of statistics on a scale of 0 (very stupid) to 100 (very nice). Interestingly, students seem to find statistics quite nice: the sample mean equals 83. The sample standard deviation equals 7. We know that the standard deviation in the population (all BS students) is 8. Calculate the 90% confidence interval. 1 point(81.53, 84.47) (81.24, 84.76) (81.32, 84.68) (80.99, 85.01)

Question 2381 random elementary schools were asked for their average exam scores (sample mean = 535, sample standard deviation = 7). Calculate the 98% confidence interval.1 point(528.00, 542.00)(533.15, 536.85)Not possible to calculate based on this information.(533.41, 536.59)

Confidence IntervalsThe scores of 10-year-old children on an IQ test has a standard deviation of 12. Let’s suppose for a sample of 36 children, the mean IQ comes out to be 75. What is the interval in which the population mean will belong if you want to be 90% confident of your estimation?(74.45, 75.55)(71.63, 78.37)(70.87, 79.14)(71.71, 78.29)

The scores of a random sample of 100 high school students on a standardized mathematics test in school A gave a mean of 78 and a standard deviation of 20. What is the best point estimate of the true average score in this standardized mathematics test?

Question 4Your instructor tells you that the recent exam had a mean of 80 points and a standard deviation of 2.3. Interpret the standard deviation value in everyday language.1 pointThe maximum score was 82.3.Most students earned an 80 on the exam.The typical score was 2.3 points away from the mean.The range of scores was 4.6.

A sample of size =n90 is drawn from a normal population whose standard deviation is =σ9.7. The sample mean is =x38.78.Part: 0 / 20 of 2 Parts CompletePart 1 of 2(a) Construct an 80% confidence interval for μ. Round the answer to at least two decimal places.An 80% confidence interval for the mean is <<μ.