A shopkeeper bought two mobile phones in ₹ 8000. If he sells 1st phone at 20% profit and 2nd phone at 15% profit he earns certain profit. But if he sells 1st phone at 15% profit and 2nd phone at 20% profit he gets ₹ 100 more. Find the price of both the phones.₹ 3500, ₹ 4500₹ 3000, ₹ 5000₹ 4000, ₹ 4000₹ 2000, ₹ 6000
Question
A shopkeeper bought two mobile phones in ₹ 8000. If he sells 1st phone at 20% profit and 2nd phone at 15% profit he earns certain profit. But if he sells 1st phone at 15% profit and 2nd phone at 20% profit he gets ₹ 100 more. Find the price of both the phones.₹ 3500, ₹ 4500₹ 3000, ₹ 5000₹ 4000, ₹ 4000₹ 2000, ₹ 6000
Solution
Let's denote the cost price of the first phone as x and the cost price of the second phone as y.
From the problem, we know that:
x + y = 8000 (since the shopkeeper bought both phones for ₹ 8000)
We also know that if the shopkeeper sells the first phone at 20% profit and the second phone at 15% profit, he earns a certain profit. But if he sells the first phone at 15% profit and the second phone at 20% profit, he gets ₹ 100 more.
This gives us the equation:
0.20x + 0.15y = 0.15x + 0.20y + 100
Solving this equation gives us:
0.05x = 0.05y + 100
or
x = y + 2000
Substituting x = y + 2000 into the first equation gives us:
y + 2000 + y = 8000
or
2y = 6000
or
y = 3000
Substituting y = 3000 into x = y + 2000 gives us:
x = 3000 + 2000 = 5000
So, the cost price of the first phone is ₹ 5000 and the cost price of the second phone is ₹ 3000. Therefore, the correct answer is ₹ 3000, ₹ 5000.
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