In village A, there are 40% females. The number of males in Village B is double of the number of males in village A. The number of males and females in village B is equalThe difference between the total number of male and female population of village A is 500. Then find the total number of female populations of both the villages.a.2500b.4000c.3500d.1800
Question
In village A, there are 40% females. The number of males in Village B is double of the number of males in village A. The number of males and females in village B is equalThe difference between the total number of male and female population of village A is 500. Then find the total number of female populations of both the villages.a.2500b.4000c.3500d.1800
Solution
Let's solve this step by step:
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Let's assume the total population of village A is P. According to the problem, 40% of P are females, so 60% of P are males.
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The difference between the number of males and females in village A is 500. So, we can write the equation: 0.60P - 0.40P = 500. Solving this equation gives P = 2500.
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So, the number of males in village A is 0.60 * 2500 = 1500 and the number of females in village A is 0.40 * 2500 = 1000.
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The number of males in village B is double the number of males in village A, so there are 2 * 1500 = 3000 males in village B.
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The number of males and females in village B is equal, so there are also 3000 females in village B.
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Therefore, the total number of females in both villages is 1000 (from village A) + 3000 (from village B) = 4000.
So, the answer is (b) 4000.
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