Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Question
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Solution
Let's solve this step by step:
Step 1: Let's assume Ronit's current age is x years. According to the problem, Ronit's father's age is 3x years.
Step 2: After 8 years, Ronit's age will be x + 8 years and his father's age will be 3x + 8 years. According to the problem, at this time, the father's age is two and a half times Ronit's age. So, we can set up the equation: 3x + 8 = 2.5 * (x + 8).
Step 3: Solving this equation, we get x = 16. So, Ronit is 16 years old and his father is 48 years old.
Step 4: After further 8 years, Ronit will be 16 + 8 + 8 = 32 years old and his father will be 48 + 8 + 8 = 64 years old.
Step 5: At this time, the father's age is 64/32 = 2 times Ronit's age.
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