The relationship between the radius of curvature (R) and the steering angle (δ) for a bicycle can be given by the formula:

R = L / tan(δ)

where L is the length of the bicycle. In this case, it is given that L = 1m and R = 1m. Substituting these values into the formula, we get:

1 = 1 / tan(δ)

Solving for δ, we get:

tan(δ) = 1

Therefore, δ = arctan(1)

The arctangent of 1 is π/4 radians. So, the steering angle should be π/4 radians for the bicycle to travel in a circle of radius 1m.

So, the answer is C. π/4.

Question

The relationship between the radius of curvature (R) and the steering angle (δ) for a bicycle can be given by the formula:

R = L / tan(δ)

where L is the length of the bicycle. In this case, it is given that L = 1m and R = 1m. Substituting these values into the formula, we get:

1 = 1 / tan(δ)

Solving for δ, we get:

tan(δ) = 1

Therefore, δ = arctan(1)

The arctangent of 1 is π/4 radians. So, the steering angle should be π/4 radians for the bicycle to travel in a circle of radius 1m.

So, the answer is C. π/4.

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