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The names of 5 students from section A, 6 from section B and 7 students from section C were selected. The age of all the 18 students was different. Again, one name was selected from them and it was found that it was of section B. What was the probability that it was the youngest student of the section B?Options1/181/61/121/15

Question

The names of 5 students from section A, 6 from section B and 7 students from section C were selected. The age of all the 18 students was different. Again, one name was selected from them and it was found that it was of section B. What was the probability that it was the youngest student of the section B?Options1/181/61/121/15

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Solution

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of outcomes.

In this case, the total number of students is 18 (5 from section A, 6 from section B, and 7 from section C).

The favorable outcome is that the selected student is the youngest from section B. Since the age of all the students is different, there can only be one youngest student in each section. So, there is only 1 favorable outcome.

Therefore, the probability is 1/18. So, the correct option is 1/18.

This problem has been solved

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