Assume a typical value of n=3.6 for the refractive index of an LED material. What percentage of the internally generated optical power is emitted into an air medium?
Question
Assume a typical value of n=3.6 for the refractive index of an LED material. What percentage of the internally generated optical power is emitted into an air medium?
Solution
To calculate the percentage of the internally generated optical power emitted into an air medium, we need to use the formula for the power transmission coefficient (T) at the interface between two media with different refractive indices. This formula is given by:
T = (4n1n2) / (n1 + n2)^2
where n1 and n2 are the refractive indices of the two media. In this case, n1 = 3.6 (the refractive index of the LED material) and n2 = 1 (the refractive index of air).
Substituting these values into the formula, we get:
T = (43.61) / (3.6 + 1)^2 = 14.4 / 21.16 = 0.6803
To convert this to a percentage, we multiply by 100, giving:
T = 0.6803 * 100 = 68.03%
So, approximately 68.03% of the internally generated optical power is emitted into an air medium.
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