A shed is in the shape of a rectangular box with a triangular prism on top. The shed is 12 m long. The base of the rectangular box is 4 m wide and the walls are 2.5 m high. The full height, including the walls and the height of the triangular prism, is 5 m.Calculate the volume of the shed.

A shed is in the shape of a rectangular box with a triangular prism on top. The shed is 12 m long. The base of the rectangular box is 4 m wide and the walls are 2.5 m high. The full height, including the walls and the height of the triangular prism, is 5 m.

A company rents storage sheds shaped like rectangular prisms. Each shed is 12 feet long, 8 feet wide, and 10 feet tall. The rental cost is $3 per cubic foot. How much does it cost to rent one shed?$

The ratio of the length to the breadth to the height of a box is 5 : 3 : 4. If the length is 12 cm longer than the breadth, find its volume.Volume: ____ cm³.

The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a height of 6 units, and the right cylinder has a height of 4 units. Which conclusion can be made from the given information?Group of answer choicesThe volume of the triangular prism is half the volume of the cylinder.The volume of the triangular prism is twice the volume of the cylinder.The volume of the triangular prism is equal to the volume of the cylinder.The volume of the triangular prism is not equal to the volume of the cylinder.

Consider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have.(a) Draw several diagrams to illustrate the situation, some short boxes with large bases and some tall boxes with small bases. Find the volumes of several such boxes.(b) Draw a diagram illustrating the general situation. Let x denote the length of the side of the square being cut out. Let y denote the length of the base.(c) Write an expression for the volume V in terms of both x and y.V = x(3−2x)(3−2x) (d) Use the given information to write an equation that relates the variables x and y.y=3−2x (e) Use part (d) to write the volume as a function of only x.V(x) = x(3−2x)(3−2x) (f) Finish solving the problem by finding the largest volume that such a box can have.V = ft3