4/7 of the girls and 1/5 of the boys of a primary school participated in the annual sports. If the number of participating students is 420 out of which 124 are boys, what is the total number of students in the primary school?Options854828716834802
Question
4/7 of the girls and 1/5 of the boys of a primary school participated in the annual sports. If the number of participating students is 420 out of which 124 are boys, what is the total number of students in the primary school?Options854828716834802
Solution
To solve this problem, we first need to find out the number of girls who participated in the annual sports. We know that the total number of participating students is 420, out of which 124 are boys. So, the number of girls who participated is 420 - 124 = 296.
We know that this number, 296, represents 4/7 of the total number of girls in the school. To find the total number of girls, we can set up the equation 4/7 * G = 296, where G is the total number of girls. Solving for G gives us G = 296 * 7/4 = 518.
Similarly, the number of boys who participated, 124, represents 1/5 of the total number of boys in the school. Setting up the equation 1/5 * B = 124, where B is the total number of boys, and solving for B gives us B = 124 * 5/1 = 620.
Adding the total number of girls and boys gives us the total number of students in the school, which is 518 + 620 = 1138.
So, the total number of students in the primary school is 1138. However, this option is not available in the given options. There might be a mistake in the problem or the options provided.
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