QD=a−bP, P=2, d(a−2b)/(a−2b)=? ​

Given the equation QD = a - bP, and P = 2, we can substitute P into the equation to get:

QD = a - 2b

The derivative of a function measures the sensitivity to change of the function value (output value) with respect to a change in its argument (input value).

The derivative of a constant is zero, and the derivative of a variable with respect to itself is 1.

So, the derivative of (a - 2b) with respect to (a - 2b) is 1.

Therefore, d(a - 2b) / d(a - 2b) = 1.