B is twice efficient than A and the total time taken to complete the work by both A and B together is 22 days. Find thenumber of days taken by B to complete the work alone.

B is twice as efficient as A and A can do a piece of work in 21 days. A started the work and after a few days B joined him. They completed the work in 15 days from starting. For how many days did they work together?Select one:a. 2 daysb. 3 daysc. 6 1/2 daysd. 5 dayse. 6 days

when working alone A takes 24 more days than time taken by A and B together to finish certain work. If A is 50% more efficient than B, then find the time taken by B to finish the work alone.

A and B can do a work in 30 days. If A worked twice as fast and B worked one-fourth as efficiently as he usually does, the work would still be completed in 30 days. Find the time taken (in days) by A alone to do the work.

If A is 25% as efficient as B and can complete a certain work taking 15 days more than the time taken by B, in how many days will both A and B together complete the work?4 days5 days7 days10 days

Select the correct answerA, B and C together can finish a piece of work in 30 days. If A and C is twice efficient than B. A and B is thrice efficient than C in how many days A alone can complete the work?Options84 days80 days75 days72 days