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Alleles A and B are linked on chromosome 1 (such that you have A-B and a-b). Alleles C and D are linked on chromosome 2 (you have C-D and c-d). If a crossover event does not occur between either set of genes, which gamete genotype could NOT be produced by an individual heterozygous at each locus?

Question

Alleles A and B are linked on chromosome 1 (such that you have A-B and a-b). Alleles C and D are linked on chromosome 2 (you have C-D and c-d). If a crossover event does not occur between either set of genes, which gamete genotype could NOT be produced by an individual heterozygous at each locus?

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Solution

The individual is heterozygous at each locus, meaning they have both dominant and recessive alleles for each gene. The genotype for this individual would be AaBbCcDd.

The linked genes are A-B on chromosome 1 and C-D on chromosome 2. This means that during meiosis, these genes will be inherited together unless a crossover event occurs.

If no crossover event occurs, the possible gametes that could be produced are AB/CD (from the dominant alleles) and ab/cd (from the recessive alleles).

Therefore, the gamete genotype that could NOT be produced without a crossover event is a mix of dominant and recessive alleles from each linked set, such as Ab/Cd or aB/cD. These combinations would require a crossover event to separate the linked dominant and recessive alleles.

This problem has been solved

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