Two identical point charges are separated at 10cm. What is the magnitude of the two identical point charges if their electric potential energy is at 90 Joules?Group of answer choices300000 C0.003 C3x10^-5 J3x10^-5 C
Question
Two identical point charges are separated at 10cm. What is the magnitude of the two identical point charges if their electric potential energy is at 90 Joules?Group of answer choices300000 C0.003 C3x10^-5 J3x10^-5 C
Solution
The formula for the electric potential energy (U) between two point charges is given by:
U = k * q1 * q2 / r
where:
- k is Coulomb's constant (8.99 * 10^9 N m^2/C^2),
- q1 and q2 are the charges (in Coulombs),
- r is the distance between the charges (in meters).
Given that the two charges are identical, we can say q1 = q2 = q. Also, the distance r is given as 10 cm, which is 0.1 m. The electric potential energy U is given as 90 Joules. Substituting these values into the formula, we get:
90 = k * q * q / 0.1
Solving for q, we get:
q = sqrt((90 * 0.1) / k)
Substituting the value of k, we get:
q = sqrt((90 * 0.1) / (8.99 * 10^9))
Solving this, we get:
q = 3 * 10^-5 C
So, the magnitude of the two identical point charges is 3 * 10^-5 C.
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