Given Boolean expression: F(A,B) = AB + A’B’a) Write the truth table for the above Boolean expression.b) Draw the schematic diagram for the above Boolean expression.c) Write the Verilog code for the Boolean expression and then compare testbench generatedwaveform with the truth table to verify your circuit.

a) Truth Table:

b) Schematic Diagram:

The schematic diagram would consist of two AND gates and one OR gate. The inputs A and B would go to one AND gate, and the inverted inputs A' and B' would go to the other AND gate. The outputs of both AND gates would then go to the OR gate, whose output would be F(A,B).

c) Verilog Code:

module top;
  reg A, B;
  wire F;

  assign F = (A & B) | (~A & ~B);

  initial begin
    $monitor("A = %b, B = %b, F = %b", A, B, F);

    A = 0; B = 0; #10;
    A = 0; B = 1; #10;
    A = 1; B = 0; #10;
    A = 1; B = 1; #10;

    $finish;
  end
endmodule

This Verilog code first declares A and B as registers, and F as a wire. It then assigns F the value of the Boolean expression AB + A'B'. The initial block then tests all possible combinations of A and B, and monitors the output F for each combination. The #10 delays are there to ensure that the simulation doesn't run too quickly.

To verify the circuit, you would compare the output of the Verilog simulation with the truth table. The output F should match the F column in the truth table for each combination of A and B.