Alex is teaching a class on number properties and wants to create an exercise for his students. He needs a program that takes a three-digit number as input, calculates the sum of its digits, and determines whether the sum is even or odd.
Question
Alex is teaching a class on number properties and wants to create an exercise for his students. He needs a program that takes a three-digit number as input, calculates the sum of its digits, and determines whether the sum is even or odd.
Solution
Sure, here is a step-by-step guide to create such a program:
-
First, you need to create a function that takes a three-digit number as input. You can do this using the
input()function. -
Next, you need to calculate the sum of the digits. You can do this by converting the number to a string, iterating over each character in the string, converting each character back to an integer, and adding them all together.
-
After you have the sum of the digits, you need to determine whether the sum is even or odd. You can do this using the modulus operator (
%). If the sum modulo 2 is 0, then the sum is even. Otherwise, it's odd. -
Finally, you need to print out whether the sum is even or odd. You can do this using the
print()function.
Here is a sample code that implements these steps:
# Step 1: Get the input
number = input("Enter a three-digit number: ")
# Step 2: Calculate the sum of the digits
digit_sum = sum(int(digit) for digit in str(number))
# Step 3: Determine whether the sum is even or odd
if digit_sum % 2 == 0:
result = "even"
else:
result = "odd"
# Step 4: Print the result
print("The sum of the digits is", result)
This program will take a three-digit number as input, calculate the sum of its digits, and print whether the sum is even or odd.
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