The vertex of a parabolic function given in the form f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

In this case, a = 1 and b = 3. So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -3/2.

To find the y-coordinate of the vertex, we substitute x = -3/2 into the function:

f(-3/2) = (-3/2)^2 + 3*(-3/2) + 2 = 9/4 - 9/2 + 2 = -1/4.

So, the vertex of the function f(x) = x^2 + 3x + 2 is (-3/2, -1/4), which corresponds to option c.

Question

The vertex of a parabolic function given in the form f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

In this case, a = 1 and b = 3. So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -3/2.

To find the y-coordinate of the vertex, we substitute x = -3/2 into the function:

f(-3/2) = (-3/2)^2 + 3*(-3/2) + 2 = 9/4 - 9/2 + 2 = -1/4.

So, the vertex of the function f(x) = x^2 + 3x + 2 is (-3/2, -1/4), which corresponds to option c.

Knowee AI · Accepted Answer

The vertex of a parabolic function given in the form f(x) = ax^2 + bx + c is given by the point (-b/2a, f(-b/2a)).

In this case, a = 1 and b = 3. So, the x-coordinate of the vertex is -b/2a = -3/(2*1) = -3/2.

To find the y-coordinate of the vertex, we substitute x = -3/2 into the function:

f(-3/2) = (-3/2)^2 + 3*(-3/2) + 2 = 9/4 - 9/2 + 2 = -1/4.

So, the vertex of the function f(x) = x^2 + 3x + 2 is (-3/2, -1/4), which corresponds to option c.

What is the vertex of f(x) = x2 + 3x + 2?Question 26Select one:a.7b.(0, 2)c.(-3/2, -1/4)d.-3/2e.None of these