A certain molecular compound M has a solubility in acetone of 20.0gL at 5.°C. Calculate the mass of M that's dissolved in 5.0L of a saturated solution of M in acetone at this temperature.Be sure your answer has the correct unit symbol and number of significant digits.
Question
A certain molecular compound M has a solubility in acetone of 20.0gL at 5.°C. Calculate the mass of M that's dissolved in 5.0L of a saturated solution of M in acetone at this temperature.Be sure your answer has the correct unit symbol and number of significant digits.
Solution 1
First, we need to convert the solubility of compound M from g/L to g.
Given that the solubility of M is 20.0 g/L, we can calculate the mass of M in 5.0 L of solution by multiplying the solubility by the volume of the solution:
20.0 g/L * 5.0 L = 100.0 g
Therefore, 100.0 g of compound M will be dissolved in 5.0 L of a saturated solution of M in acetone at 5.°C.
The answer has the correct unit symbol (g for grams) and the correct number of significant digits (4).
Solution 2
First, we need to convert the solubility of compound M from g/L to g/5L because the volume of the solution given in the problem is 5L.
The solubility of M is given as 20.0 g/L.
So, the amount of M that can be dissolved in 5.0L of acetone is:
20.0 g/L * 5.0 L = 100.0 g
Therefore, 100.0 g of compound M can be dissolved in 5.0L of a saturated solution of M in acetone at 5°C.
The answer has the correct unit symbol (g) and the correct number of significant digits (4).
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