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A line passes through the points (–10,12) and (14,12). Write its equation in slope-intercept form.

Question

A line passes through the points (–10,12) and (14,12). Write its equation in slope-intercept form.

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Solution

The slope-intercept form of a line is given by y = mx + b, where m is the slope of the line and b is the y-intercept.

Step 1: Find the slope (m) The slope of a line passing through the points (x1, y1) and (x2, y2) is given by (y2 - y1) / (x2 - x1).

For the points (–10,12) and (14,12), the slope m = (12 - 12) / (14 - -10) = 0 / 24 = 0.

Step 2: Find the y-intercept (b) Since the line passes through the points (–10,12) and (14,12), we know that when x = -10 or 14, y = 12.

So, we can use the slope we found and one of the points to find the y-intercept. If we use the point (–10,12), we substitute these values into the equation y = mx + b to get 12 = 0*(-10) + b. Solving for b gives b = 12.

Step 3: Write the equation of the line Now that we have the slope m = 0 and the y-intercept b = 12, we can write the equation of the line in slope-intercept form as y = 0x + 12, or simply y = 12.

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