What is the gravitational force experienced by an object of 10 kg, 200 m away from an object weighing 1000 kg?*1 point1.6675 x 10^-11 N2.6675 x 10^-11 N3.6675 x 10^-11 N4.6675 x 10^-11 N
Question
What is the gravitational force experienced by an object of 10 kg, 200 m away from an object weighing 1000 kg?*1 point1.6675 x 10^-11 N2.6675 x 10^-11 N3.6675 x 10^-11 N4.6675 x 10^-11 N
Solution 1
The gravitational force between two objects can be calculated using Newton's law of universal gravitation. The formula is:
F = G * (m1 * m2) / r^2
where:
- F is the force between the masses,
- G is the gravitational constant,
- m1 and m2 are the two masses,
- r is the distance between the centers of the two masses.
Given:
- G = 6.674 * 10^-11 N(m/kg)^2,
- m1 = 10 kg (the mass of the first object),
- m2 = 1000 kg (the mass of the second object),
- r = 200 m (the distance between the two objects).
Substituting these values into the formula, we get:
F = 6.674 * 10^-11 * (10 * 1000) / 200^2
Solving this equation will give us the gravitational force experienced by the 10 kg object.
Let's calculate it:
F = 6.674 * 10^-11 * 10000 / 40000 F = 6.674 * 10^-11 * 0.25 F = 1.6685 * 10^-11 N
So, the closest answer is 1.6675 x 10^-11 N.
Solution 2
The gravitational force between two objects can be calculated using Newton's law of universal gravitation. The formula is:
F = G * (m1 * m2) / r^2
where:
- F is the force between the masses,
- G is the gravitational constant,
- m1 and m2 are the two masses,
- r is the distance between the centers of the two masses.
Given:
- G = 6.674 * 10^-11 N(m/kg)^2,
- m1 = 10 kg (the mass of the first object),
- m2 = 1000 kg (the mass of the second object),
- r = 200 m (the distance between the two objects).
Substituting these values into the formula, we get:
F = 6.674 * 10^-11 * (10 * 1000) / 200^2
Solving this equation will give us the gravitational force experienced by the 10 kg object.
Let's calculate it:
F = 6.674 * 10^-11 * 10000 / 40000 F = 6.674 * 10^-11 * 0.25 F = 1.6685 * 10^-11 N
So, the closest answer to this result is 1.6675 x 10^-11 N.
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