Assume three (03) channels, each with an 80 kF{z bandwidth, are to be multiplexedtogether into a link with a bandwidth of 300 kHz, from 200kllz to 500 kFIz usingFDM. Find the bandwidth of the each channel on the link,i. Ifthere are no guard bands.ii. If there is a guard band of 20 kHz between the channels.
Question
Assume three (03) channels, each with an 80 kF{z bandwidth, are to be multiplexedtogether into a link with a bandwidth of 300 kHz, from 200kllz to 500 kFIz usingFDM. Find the bandwidth of the each channel on the link,i. Ifthere are no guard bands.ii. If there is a guard band of 20 kHz between the channels.
Solution
To find the bandwidth of each channel on the link using FDM, we need to consider two scenarios: one without guard bands and one with a guard band of 20 kHz between the channels.
i. Without guard bands: Since there are three channels to be multiplexed together, and the total bandwidth of the link is 300 kHz, we can divide the total bandwidth equally among the channels. Therefore, each channel will have a bandwidth of 300 kHz divided by 3, which is 100 kHz.
ii. With a guard band of 20 kHz between the channels: In this case, we need to account for the guard band when calculating the bandwidth of each channel. The total bandwidth required for each channel, including the guard band, will be the sum of the channel bandwidth and the guard band width.
So, each channel will have a bandwidth of 80 kHz (channel bandwidth) + 20 kHz (guard band width), which is equal to 100 kHz.
Therefore, in both scenarios, the bandwidth of each channel on the link will be 100 kHz.
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