We have four sources, each creating 250 8-bit characters per second. If the interleaved unit is a character and 1 synchronizing bit is added to each frame, find (a) the data rate of each source, (b) the duration of each character in each source, (c) the frame rate, (d) the duration of each frame, (e) the number of bits in each frame

(a) The data rate of each source:

Each character is 8 bits and each source is creating 250 characters per second. Therefore, the data rate of each source is 250 characters/second * 8 bits/character = 2000 bits/second.

(b) The duration of each character in each source:

The duration of each character can be found by taking the reciprocal of the rate of character generation. Therefore, the duration of each character is 1 / 250 characters/second = 0.004 seconds/character.

(c) The frame rate:

If the interleaved unit is a character, then each frame consists of one character from each of the four sources, plus one synchronizing bit. Therefore, each frame is 4 characters + 1 bit = 33 bits. The frame rate is the data rate of each source divided by the number of bits in each frame, so the frame rate is 2000 bits/second / 33 bits/frame = approximately 60.6 frames/second.

(d) The duration of each frame:

The duration of each frame is the reciprocal of the frame rate. Therefore, the duration of each frame is 1 / 60.6 frames/second = approximately 0.0165 seconds/frame.

(e) The number of bits in each frame:

As mentioned in part (c), each frame consists of one character from each of the four sources, plus one synchronizing bit. Therefore, each frame is 4 characters * 8 bits/character + 1 bit = 33 bits.