To solve this problem, we need to use the formula for the period of a spring-mass system, which is T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. We can rearrange this formula to solve for k: k = 4π²m/T².

First, we need to find the period of one cycle. We know that the mass goes through 10 cycles in 6.50 s, so one cycle takes 6.50 s / 10 = 0.65 s.

Now we can substitute the given values into the formula:

k = 4π²(0.200 kg) / (0.65 s)²
k = 4π²(0.200 kg) / 0.4225 s²
k = 5.94 N/m

So, the closest answer is d. 5.95 N/m.

Question

To solve this problem, we need to use the formula for the period of a spring-mass system, which is T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. We can rearrange this formula to solve for k: k = 4π²m/T².

First, we need to find the period of one cycle. We know that the mass goes through 10 cycles in 6.50 s, so one cycle takes 6.50 s / 10 = 0.65 s.

Now we can substitute the given values into the formula:

k = 4π²(0.200 kg) / (0.65 s)²
k = 4π²(0.200 kg) / 0.4225 s²
k = 5.94 N/m

So, the closest answer is d. 5.95 N/m.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for the period of a spring-mass system, which is T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. We can rearrange this formula to solve for k: k = 4π²m/T².

First, we need to find the period of one cycle. We know that the mass goes through 10 cycles in 6.50 s, so one cycle takes 6.50 s / 10 = 0.65 s.

Now we can substitute the given values into the formula:

k = 4π²(0.200 kg) / (0.65 s)²
k = 4π²(0.200 kg) / 0.4225 s²
k = 5.94 N/m

So, the closest answer is d. 5.95 N/m.

A 0.200 kg mass attached to the end of a spring moves up and down through 10 cycles in6.50 s. What is the force constant of the springa. 18.7 N/m b. 4.67 N/m c. 22.8 N/m d. 5.95 N/m e. 12.0 N

Question

Solution

Similar Questions

Upgrade your grade with Knowee