There are 3 persons- A, B and C. On some days, A lent tractors to B and C as many as they had. After a month B gave as many tractors to A and C as many as they had. After a month C did the same thing. At the end of this transaction each one of them had 16. Find the tractors each originally had?⚡a26, 14, 8b25, 19, 4c22, 15, 6d20, 19, 8
Question
There are 3 persons- A, B and C. On some days, A lent tractors to B and C as many as they had. After a month B gave as many tractors to A and C as many as they had. After a month C did the same thing. At the end of this transaction each one of them had 16. Find the tractors each originally had?⚡a26, 14, 8b25, 19, 4c22, 15, 6d20, 19, 8
Solution
This problem can be solved by working backwards.
Step 1: At the end of the transaction, each person had 16 tractors. This means that before C gave away his tractors, A and B had 16 each and C had 16*2 = 32 tractors.
Step 2: Before B gave away his tractors, A and C had 32 each and B had 32*2 = 64 tractors.
Step 3: Finally, before A gave away his tractors, B and C had 64 each and A had 64*2 = 128 tractors.
So, originally, A had 128 tractors, B had 64 tractors, and C had 32 tractors. However, these numbers do not match any of the options provided. There seems to be a mistake in the problem or the options.
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