Give a table:Student (studentId, name, major) Primary key is [studentId, major].Which code snippet will list out students that the major not equals 'IT'?SELECT * FROM Student HAVING major <> 'IT'All of the aboveSELECT * FROM Student s WHERE s.major != 'IT'SELECT * FROM Student GROUP BY major HAVING major <> 'IT'
Question
Give a table:Student (studentId, name, major) Primary key is [studentId, major].Which code snippet will list out students that the major not equals 'IT'?SELECT * FROM Student HAVING major <> 'IT'All of the aboveSELECT * FROM Student s WHERE s.major != 'IT'SELECT * FROM Student GROUP BY major HAVING major <> 'IT'
Solution
The correct code snippet to list out students whose major is not 'IT' would be:
SELECT * FROM Student s WHERE s.major != 'IT'
This SQL statement selects all columns for rows in the Student table where the major column is not equal to 'IT'. The other options are incorrect because the HAVING clause is typically used with the GROUP BY clause to filter group results, not individual rows.
Similar Questions
Consider these following tables and only solve the query. Tables: 1) student: s_no (primary key), student_name, course_no (foreign key), age 2) courser-course-no (primary key), course-name.
Given 3 tables, students(id, name) , courses(id, name) , grades(id, course_id, student_id, grade), find the name of the most popular course (the one with the most enrolled students and students should be passing, i.e. achieving a grade of at least 50) and if there is a tie, get the course name that's lexicographically smaller. Your query should output a table with the following columns (name)
Students Table Surname First_Name Student_No Dept_No Year Duke Fitzroy 1 4 2Al-Essawy Zaid 2 4 2Ayton Phil 3 3 1Patel Mahesh 4 2 1Jones Gareth 5 2 1Scott Gavin 6 2 2CREATE VIEW Freshman AS Select * From Students Where Year = 2;Considering the above Students table and Freshman view, what will be the result of the following SQL query:Select * From Freshman Where Dept_No=2;Question 8Select one:a. Surname First_Name Student_No Dept_No Year Duke Fitzroy 1 4 2Al-Essawy Zaid 2 4 2b. Surname First_Name Student_No Dept_No Year PatelMahesh4 2 1JonesGareth5 2 1 Scott Gavin 6 2 2c. Surname First_Name Student_No Dept_No Year Scott Gavin6 2 2d. Surname First_Name Student_No Dept_No Year PatelMahesh4 2 1Jones Gareth 5
SELECT *FROM student JOIN takes USING (ID);The above query is equivalent toSELECT *FROM student INNER JOIN takes USING (ID);SELECT *FROM student LEFT OUTER JOIN takes USING (ID);NONE OF the mentionedSELECT *FROM student OUTER JOIN takes USING (ID);
You are given the following tables:CourseCourseID Description CreditsCS101 Computer Science I 3CS201 Elementary Data Structures 3ENGL210 Technical Writing 3RegistrationSID CourseID SemID Instructor Grade282712 ENGL210 201701 H. Zacny B+362112 CS101 201701 K. Ross CWhat would the following SQL Select statement produce for output?select course.description, registration.SID,registration.gradefrom registration right join courseon registration.courseID = course.courseIDSelect one:a.Computer Science I 362112 Cb.Computer Science I 362112 CTechnical Writing 28212 B+c.Computer Science I 362112 CElementary Data Structures null nullTechnical Writing 28212 B+d.No results due to syntax errorClear my choiceSkip Quiz navigationQuiz navigationQuestion1Question2Question3Question4Question5Question6Question7Question8Question9Question10Question11Question12Question13Question14Question15Question16Question17Question18Question19Question20Question21Question22Question23Question24Question25Question26Question27Question28Question29Question30Question31Question32Question33Question34Question35Question36Question37Question38Question39Question40Question41Question42Question43Question44Question45Question46This pageQuestion47This pageQuestion48This pageQuestion49This pageQuestion50This page
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.