If f(x) = x3 – x2 + 100x + 1001, thenf(2000) > f(2001)f(x + 1) > f(x – 1)f(3x – 5) > f(3x)

The text you provided seems to be a set of mathematical inequalities involving a cubic function f(x) = x^3 - x^2 + 100x + 1001. However, you didn't provide a specific question. Are you asking whether these inequalities are true or not? If so, here's how you can approach each one:

1. f(2000) > f(2001): To check this, simply substitute x = 2000 and x = 2001 into the function and compare the results.

2. f(x + 1) > f(x – 1): This is a more general inequality. To check if it's true, you could try a few different values of x and see if the inequality holds.

3. f(3x – 5) > f(3x): Again, this is a general inequality. You could try a few different values of x to see if it holds.

Remember, for an inequality to be true for all x, it must hold for all possible values of x. If you find even one value of x for which the inequality is not true, then the inequality is not true in general.