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Factor completely.x, cubed, plus, 4, x, squared, plus, 4, x, plus, 16x 3 +4x 2 +4x+16

Question

Factor completely.x, cubed, plus, 4, x, squared, plus, 4, x, plus, 16x 3 +4x 2 +4x+16

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Solution

The given expression is x^3 + 4x^2 + 4x + 16.

To factor this completely, we first look for any common factors, but in this case, there are none.

Next, we look for patterns or special factoring formulas. This expression is in the form of a cubic equation and it seems to be a sum of cubes.

The sum of cubes formula is a^3 + b^3 = (a + b)(a^2 - ab + b^2).

In our case, a is x and b is 2, because (2)^3 = 8 and (x)^3 = x^3.

So, we can rewrite the expression as (x + 2)(x^2 - 2x + 4).

This is the completely factored form of the given expression.

This problem has been solved

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