The force required to hold the gun in position can be calculated using Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.

1. First, we need to calculate the momentum of each bullet, which is the product of its mass and velocity. So, the momentum of each bullet is m*v.

2. The total momentum of n bullets fired per second is n*m*v.

3. According to the law of conservation of momentum, the total momentum before the bullets are fired is equal to the total momentum after they are fired. Since the gun is initially at rest, its initial momentum is zero. Therefore, the momentum of the gun after the bullets are fired is equal to the total momentum of the bullets, but in the opposite direction. So, the momentum of the gun is -n*m*v.

4. The force required to hold the gun in position is the change in momentum of the gun per unit time. Since the gun is firing n bullets per second, the time interval is 1 second. Therefore, the force is (-n*m*v) / 1 = -n*m*v.

5. The negative sign indicates that the force is exerted in the opposite direction to the motion of the bullets. Therefore, the force required to hold the gun in position is n*m*v.

Question

The force required to hold the gun in position can be calculated using Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.

1. First, we need to calculate the momentum of each bullet, which is the product of its mass and velocity. So, the momentum of each bullet is m*v.

2. The total momentum of n bullets fired per second is n*m*v.

3. According to the law of conservation of momentum, the total momentum before the bullets are fired is equal to the total momentum after they are fired. Since the gun is initially at rest, its initial momentum is zero. Therefore, the momentum of the gun after the bullets are fired is equal to the total momentum of the bullets, but in the opposite direction. So, the momentum of the gun is -n*m*v.

4. The force required to hold the gun in position is the change in momentum of the gun per unit time. Since the gun is firing n bullets per second, the time interval is 1 second. Therefore, the force is (-n*m*v) / 1 = -n*m*v.

5. The negative sign indicates that the force is exerted in the opposite direction to the motion of the bullets. Therefore, the force required to hold the gun in position is n*m*v.

Knowee AI · Accepted Answer

The force required to hold the gun in position can be calculated using Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration.

1. First, we need to calculate the momentum of each bullet, which is the product of its mass and velocity. So, the momentum of each bullet is m*v.

2. The total momentum of n bullets fired per second is n*m*v.

3. According to the law of conservation of momentum, the total momentum before the bullets are fired is equal to the total momentum after they are fired. Since the gun is initially at rest, its initial momentum is zero. Therefore, the momentum of the gun after the bullets are fired is equal to the total momentum of the bullets, but in the opposite direction. So, the momentum of the gun is -n*m*v.

4. The force required to hold the gun in position is the change in momentum of the gun per unit time. Since the gun is firing n bullets per second, the time interval is 1 second. Therefore, the force is (-n*m*v) / 1 = -n*m*v.

5. The negative sign indicates that the force is exerted in the opposite direction to the motion of the bullets. Therefore, the force required to hold the gun in position is n*m*v.

If n bullets each of mass m are fired with velocity v per second from Machine gun, The force required to hold the gun in position is

Question

Solution

Similar Questions

Upgrade your grade with Knowee