Use the Hardy-Weinberg equations: p + q = 1 and p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, what percent of the population will be homozygous dominant?
Question
Use the Hardy-Weinberg equations: p + q = 1 and p2 + 2pq + q2 = 1. If the dominant allele frequency is 0.8, what percent of the population will be homozygous dominant?
Solution
The Hardy-Weinberg equations are used to calculate the frequencies of alleles and genotypes in a population. The equations are p + q = 1 and p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele, q is the frequency of the recessive allele, p^2 is the frequency of the homozygous dominant genotype, 2pq is the frequency of the heterozygous genotype, and q^2 is the frequency of the homozygous recessive genotype.
Given that the dominant allele frequency (p) is 0.8, we can use the first equation to find the recessive allele frequency (q).
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Calculate q: q = 1 - p q = 1 - 0.8 q = 0.2
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Calculate the percent of the population that is homozygous dominant (p^2): p^2 = (0.8)^2 p^2 = 0.64
So, 64% of the population will be homozygous dominant.
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