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1. Simplify: tan(x)cot(x) - cos^2(x)*5 pointstan xsin^2xcot xcos^2x2. Simplify this to a basic trigonometry function: tan(x)csc(x)*5 pointstan xsec xcot xcsc x3. What is 1/(cscx) equivalent to?*5 points1/sin(x)1/tan(x)sin(x)1/cos(x)4. What are the solutions: 2 sinθ+3=2*5 pointsπ/6,2π/37π/67π/6, 11π/65π/6

Question

  1. Simplify: tan(x)cot(x) - cos^2(x)*5 pointstan xsin^2xcot xcos^2x2. Simplify this to a basic trigonometry function: tan(x)csc(x)*5 pointstan xsec xcot xcsc x3. What is 1/(cscx) equivalent to?5 points1/sin(x)1/tan(x)sin(x)1/cos(x)4. What are the solutions: 2 sinθ+3=25 pointsπ/6,2π/37π/67π/6, 11π/65π/6
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Solution

  1. The expression tan(x)cot(x) - cos^2(x) simplifies to 1 - cos^2(x). This is because tan(x) and cot(x) are reciprocal functions, so their product is 1. The term cos^2(x) remains as it is.

  2. The expression tan(x)csc(x) simplifies to 1. This is because tan(x) is equivalent to sin(x)/cos(x) and csc(x) is the reciprocal of sin(x), so their product is 1.

  3. The expression 1/(cscx) is equivalent to sin(x). This is because csc(x) is the reciprocal of sin(x), so 1/csc(x) is equivalent to sin(x).

  4. The equation 2 sinθ+3=2 can be solved as follows: First, subtract 3 from both sides to get 2 sinθ = -1. Then, divide both sides by 2 to get sinθ = -1/2. The solutions to this equation are θ = 7π/6 and θ = 11π/6. These are the angles in the unit circle where the y-coordinate (which represents sinθ) is -1/2.

This problem has been solved

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