1. Simplify: tan(x)cot(x) - cos^2(x)*5 pointstan xsin^2xcot xcos^2x2. Simplify this to a basic trigonometry function: tan(x)csc(x)*5 pointstan xsec xcot xcsc x3. What is 1/(cscx) equivalent to?*5 points1/sin(x)1/tan(x)sin(x)1/cos(x)4. What are the solutions: 2 sinθ+3=2*5 pointsπ/6,2π/37π/67π/6, 11π/65π/6
Question
- Simplify: tan(x)cot(x) - cos^2(x)*5 pointstan xsin^2xcot xcos^2x2. Simplify this to a basic trigonometry function: tan(x)csc(x)*5 pointstan xsec xcot xcsc x3. What is 1/(cscx) equivalent to?5 points1/sin(x)1/tan(x)sin(x)1/cos(x)4. What are the solutions: 2 sinθ+3=25 pointsπ/6,2π/37π/67π/6, 11π/65π/6
Solution
-
The expression tan(x)cot(x) - cos^2(x) simplifies to 1 - cos^2(x). This is because tan(x) and cot(x) are reciprocal functions, so their product is 1. The term cos^2(x) remains as it is.
-
The expression tan(x)csc(x) simplifies to 1. This is because tan(x) is equivalent to sin(x)/cos(x) and csc(x) is the reciprocal of sin(x), so their product is 1.
-
The expression 1/(cscx) is equivalent to sin(x). This is because csc(x) is the reciprocal of sin(x), so 1/csc(x) is equivalent to sin(x).
-
The equation 2 sinθ+3=2 can be solved as follows: First, subtract 3 from both sides to get 2 sinθ = -1. Then, divide both sides by 2 to get sinθ = -1/2. The solutions to this equation are θ = 7π/6 and θ = 11π/6. These are the angles in the unit circle where the y-coordinate (which represents sinθ) is -1/2.
Similar Questions
Find the values of the other five trigonometric functions if cot x =, x lies in the third quadrant.
∫ csc x cot x 2 dx 20. ∫ 2 5 sec x tan xdx
Find the value of each of the six trigonometric functions (if it is defined) at the given real number t. Use your answers to complete the table. (If an answer is undefined, enter UNDEFINED.)t = 𝜋2t sin(t) cos(t) tan(t) csc(t) sec(t) cot(t)𝜋2
Which of the following expressions is not equivalent to cot2θ?csc 2θ + 1( ) 2csc 2θ - 1
Simplify the expression.-2(csc2θ - cot2θ) - 1
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.