To solve this problem, you can follow these steps: Step 1: Define a structure to hold the student details. In C++, it would look something like this: ```cpp struct Student { string regno; string name; string city; }; ``` Step 2: Create an array of this structure to hold the details of all students. ```cpp Student students[n]; // n is the number of students ``` Step 3: Input the details of all students. This can be done in a loop. ```cpp for(int i = 0; i students[i].regno students[i].name students[i].city; } ``` Step 4: Create a new array to hold the registration numbers of students who live in Chennai. ```cpp string chennaiStudents[n]; int count = 0; ``` Step 5: Loop through the students array and if a student lives in Chennai, add their registration number to the chennaiStudents array. ```cpp for(int i = 0; i

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To solve this problem, you can follow these steps: Step 1: Define a structure to hold the student details. In C++, it would look something like this: ```cpp struct Student { string regno; string name; string city; }; ``` Step 2: Create an array of this structure to hold the details of all students. ```cpp Student students[n]; // n is the number of students ``` Step 3: Input the details of all students. This can be done in a loop. ```cpp for(int i = 0; i < n; i++) { cin >> students[i].regno >> students[i].name >> students[i].city; } ``` Step 4: Create a new array to hold the registration numbers of students who live in Chennai. ```cpp string chennaiStudents[n]; int count = 0; ``` Step 5: Loop through the students array and if a student lives in Chennai, add their registration number to the chennaiStudents array. ```cpp for(int i = 0; i < n; i++) { if(students[i].city == "Chennai") { chennaiStudents[count] = students[i].regno; count++; } } ``` Step 6: Sort the chennaiStudents array in ascending order. You can use the sort function from the algorithm library in C++. ```cpp sort(chennaiStudents, chennaiStudents + count); ``` Step 7: Print the registration numbers of the students who live in Chennai. ```cpp for(int i = 0; i < count; i++) { cout << chennaiStudents[i] << endl; } ``` This will give you the registration numbers of all students who live in Chennai, sorted in ascending order.

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To solve this problem, you can follow these steps: Step 1: Define a structure to hold the student details. In C++, it would look something like this: ```cpp struct Student { string regno; string name; string city; }; ``` Step 2: Create an array of this structure to hold the details of all students. ```cpp Student students[n]; // n is the number of students ``` Step 3: Input the details of all students. This can be done in a loop. ```cpp for(int i = 0; i < n; i++) { cin >> students[i].regno >> students[i].name >> students[i].city; } ``` Step 4: Create a new array to hold the registration numbers of students who live in Chennai. ```cpp string chennaiStudents[n]; int count = 0; ``` Step 5: Loop through the students array and if a student lives in Chennai, add their registration number to the chennaiStudents array. ```cpp for(int i = 0; i < n; i++) { if(students[i].city == "Chennai") { chennaiStudents[count] = students[i].regno; count++; } } ``` Step 6: Sort the chennaiStudents array in ascending order. You can use the sort function from the algorithm library in C++. ```cpp sort(chennaiStudents, chennaiStudents + count); ``` Step 7: Print the registration numbers of the students who live in Chennai. ```cpp for(int i = 0; i < count; i++) { cout << chennaiStudents[i] << endl; } ``` This will give you the registration numbers of all students who live in Chennai, sorted in ascending order.

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