The batting average of a cricketer for 78 innings is 38 runs.His highest score exceeds the lowest score by 226 runs.If these two innings are excluded, the average of the remaining innings is 36 runs.What is his hightest score?150250227350

To solve this problem, we need to use the formula for calculating the average, which is the sum of all values divided by the number of values.

Step 1: Calculate the total runs scored in 78 innings. The average score is 38 runs, so the total runs scored in 78 innings is 38 * 78 = 2944 runs.

Step 2: Calculate the total runs scored in the remaining 76 innings. The average score for the remaining 76 innings is 36 runs, so the total runs scored in these innings is 36 * 76 = 2736 runs.

Step 3: Find the total runs scored in the two excluded innings. Subtract the total runs scored in the remaining 76 innings from the total runs scored in all 78 innings. This gives us 2944 - 2736 = 208 runs.

Step 4: Determine the scores of the two excluded innings. We know that the highest score exceeds the lowest score by 226 runs. Let's denote the lowest score as x. Then the highest score is x + 226. The sum of these two scores is equal to the total runs scored in the two excluded innings, so we can set up the equation: x + (x + 226) = 208.

Step 5: Solve the equation for x. This simplifies to 2x + 226 = 208. Subtract 226 from both sides to get 2x = -18. Divide both sides by 2 to get x = -9.

However, a score cannot be negative, so there must be a mistake in the problem. The highest score cannot exceed the lowest score by 226 runs if the total runs scored in the two innings is only 208. Therefore, it's not possible to determine the highest score based on the information given.