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Two waves, with amplitudes 7.0 cm and 0.50 cm,approach each other on a string. What is themaximum amplitude of the string as they passthrough each other? (9.1) K/U(a) 2.0 cm(b) 7.5 cm(c) 24 cm(d) 35 cm

Question

Two waves, with amplitudes 7.0 cm and 0.50 cm,approach each other on a string. What is themaximum amplitude of the string as they passthrough each other? (9.1) K/U(a) 2.0 cm(b) 7.5 cm(c) 24 cm(d) 35 cm

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Solution

The maximum amplitude of the string as the two waves pass through each other is simply the sum of the individual amplitudes. This is because waves add together linearly, a principle known as superposition.

So, you just add the amplitude of the first wave (7.0 cm) to the amplitude of the second wave (0.50 cm):

7.0 cm + 0.50 cm = 7.5 cm

So, the maximum amplitude of the string as the waves pass through each other is 7.5 cm. Therefore, the correct answer is (b) 7.5 cm.

This problem has been solved

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