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Gloria is responsible for monitoring the performance of two machines in a factory. She needs to determine which of the two machines is operating closest to the optimal temperature of 100 degrees Celsius using the relational operator. Assist Gloria in displaying the machine's temperature, which is closer to 100, and the difference from 100.Input format :The first line of input consists of an integer N, representing the temperature of the first machine.The second line consists of an integer M, representing the temperature of the second machine.Output format :The output prints "The integer closer to 100 is X with a difference of Y" where X is the temperature of the closer machine and Y is the difference from 100.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:1 ≤ N, M ≤ 120

Question

Gloria is responsible for monitoring the performance of two machines in a factory. She needs to determine which of the two machines is operating closest to the optimal temperature of 100 degrees Celsius using the relational operator. Assist Gloria in displaying the machine's temperature, which is closer to 100, and the difference from 100.Input format :The first line of input consists of an integer N, representing the temperature of the first machine.The second line consists of an integer M, representing the temperature of the second machine.Output format :The output prints "The integer closer to 100 is X with a difference of Y" where X is the temperature of the closer machine and Y is the difference from 100.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:1 ≤ N, M ≤ 120

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Solution 1

Here is a step-by-step guide to solve the problem:

  1. First, you need to read the temperatures of the two machines. You can do this using the input() function. Since the input function returns a string, you need to convert it to an integer using the int() function.
N = int(input())
M = int(input())
  1. Next, you need to calculate the difference of each machine's temperature from the optimal temperature of 100 degrees Celsius. You can do this by subtracting the machine's temperature from 100 and taking the absolute value to ensure the difference is positive.
diff_N = abs(100 - N)
diff_M = abs(100 - M)
  1. Now, you need to compare the two differences to determine which machine is operating closest to the optimal temperature. You can do this using an if-else statement. If the difference of the first machine is less than the difference of the second machine, then the first machine is closer to the optimal temperature. Otherwise, the second machine is closer.
if diff_N < diff_M:
    print("The integer closer to 100 is {} with a difference of {}".format(N, diff_N))
else:
    print("The integer closer to 100 is {} with a difference of {}".format(M, diff_M))
  1. The print statement inside the if-else block will display the machine's temperature which is closer to 100 and the difference from 100.

This is the complete code:

N = int(input())
M = int(input())

diff_N = abs(100 - N)
diff_M = abs(100 - M)

if diff_N < diff_M:
    print("The integer closer to 100 is {} with a difference of {}".format(N, diff_N))
else:
    print("The integer closer to 100 is {} with a difference of {}".format(M, diff_M))

This code will solve the problem as described.

This problem has been solved

Solution 2

Here is a step-by-step guide to solve the problem:

  1. First, you need to read the temperatures of the two machines. You can do this using the input() function in Python. Since the input is in integer format, you need to convert the input to integer using the int() function.
N = int(input())
M = int(input())
  1. Next, you need to calculate the difference of each machine's temperature from the optimal temperature of 100 degrees Celsius. You can do this by subtracting the machine's temperature from 100 and taking the absolute value to ensure the difference is positive.
diff_N = abs(100 - N)
diff_M = abs(100 - M)
  1. Then, you need to compare the differences of the two machines. If the difference of the first machine is less than the difference of the second machine, the first machine is closer to the optimal temperature. If the difference of the second machine is less, the second machine is closer. If the differences are equal, you can choose either machine.
if diff_N < diff_M:
    print("The integer closer to 100 is {} with a difference of {}".format(N, diff_N))
elif diff_M < diff_N:
    print("The integer closer to 100 is {} with a difference of {}".format(M, diff_M))
else:
    print("Both integers are equally close to 100 with a difference of {}".format(diff_N))

This code will display the temperature of the machine that is closest to 100 and the difference from 100.

This problem has been solved

Similar Questions

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