But-1-ene reacts with steam in the presence of a catalyst and reacts with bromine.(i) Draw the structural formula of the product of the reaction with steam in the presence of acatalyst.

The reaction of But-1-ene with steam in the presence of a catalyst is an example of hydration. The product of this reaction is an alcohol. Here's how you can draw the structural formula:

Step 1: Draw the structure of But-1-ene. It has four carbon atoms in a row (a butene), with a double bond between the first and second carbon atoms.

Step 2: In the presence of a catalyst and steam, the double bond opens up and a water molecule (H2O) adds across the double bond. The hydrogen atom from the water molecule attaches to one of the carbon atoms involved in the double bond, and the OH (hydroxyl group) attaches to the other carbon atom.

Step 3: The product is butan-2-ol. The structural formula is as follows:

H H OH H | | | | H-C-C-C-C-H | | | | H H H H

This is a simplified version of the structural formula. The actual structure would show the tetrahedral geometry around the carbon atoms.

The reaction of But-1-ene with steam in the presence of a catalyst is an example of hydration. The product of this reaction is an alcohol. Here's how you can draw the structural formula:

Step 1: Draw the structure of But-1-ene. It has four carbon atoms in a row (a butene), with a double bond between the first and second carbon atoms.

Step 2: In the presence of a catalyst and steam, the double bond opens up and a water molecule (H2O) adds across the double bond. The hydrogen atom from the water molecule attaches to one of the carbon atoms involved in the double bond, and the OH group from the water molecule attaches to the other carbon atom.

Step 3: The product is butan-2-ol. Draw the structure of butan-2-ol. It has four carbon atoms in a row (a butane), with an OH group attached to the second carbon atom.

So, the structural formula of the product is CH3-CH(OH)-CH2-CH3.