In an array-based representation of a binary tree, if a node is at index 5, what are the indices of its left and right children?a)Left: 6, Right: 7b)Left: 5, Right: 6c)Left: 10, Right: 11d)Left: 9, Right: 10
Question
In an array-based representation of a binary tree, if a node is at index 5, what are the indices of its left and right children?a)Left: 6, Right: 7b)Left: 5, Right: 6c)Left: 10, Right: 11d)Left: 9, Right: 10
Solution
The correct answer is c) Left: 10, Right: 11.
Here's the step by step explanation:
In an array-based representation of a binary tree, the children of a node at index i are at indices 2i and 2i + 1.
So, for a node at index 5:
- The left child is at index 2*5 = 10
- The right child is at index 2*5 + 1 = 11
So, the indices of the left and right children are 10 and 11 respectively.
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