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How much energy is required to vaporize 1.5 kg of aluminum? (Refer to table of latent heat values.)A.733 kJB.7095 kJC.600 kJD.1650 kJSUBMITarrow_backPREVIOUS

Question

How much energy is required to vaporize 1.5 kg of aluminum? (Refer to table of latent heat values.)A.733 kJB.7095 kJC.600 kJD.1650 kJSUBMITarrow_backPREVIOUS

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Solution

To answer this question, we need to know the latent heat of vaporization for aluminum. The latent heat of vaporization is the amount of heat energy required to change 1 kg of a substance from a liquid to a gas at constant temperature.

Let's assume that the latent heat of vaporization for aluminum is L (in kJ/kg).

The energy (E) required to vaporize a mass (m) of a substance can be calculated using the formula:

E = m * L

Given that the mass of aluminum (m) is 1.5 kg, the energy required to vaporize it would be:

E = 1.5 kg * L

Without the value of L, we cannot determine the exact amount of energy required. Please refer to your table of latent heat values to find the latent heat of vaporization for aluminum and substitute it into the formula.

This problem has been solved

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