What is the purpose of updating the left and right pointers in the Binary Search algorithm?

The purpose of updating the left and right pointers in the Binary Search algorithm is to narrow down the search range in the sorted array.

Here's the step-by-step explanation:

1. Initially, the left pointer is set at the start of the array (index 0) and the right pointer is set at the end of the array (index n-1, where n is the length of the array).

2. The algorithm calculates the middle index of the array (or sub-array) by averaging the left and right pointers. It then compares the element at the middle index with the target value.

3. If the target value is equal to the middle element, the search is successful and the algorithm returns the middle index.

4. If the target value is less than the middle element, it means the target value can only be in the left half of the array (since the array is sorted). So, the algorithm updates the right pointer to be middle index - 1, effectively ignoring the right half of the array in the next step.

5. If the target value is greater than the middle element, it means the target value can only be in the right half of the array. So, the algorithm updates the left pointer to be middle index + 1, effectively ignoring the left half of the array in the next step.

6. Steps 2-5 are repeated until the target value is found or until the left pointer is greater than the right pointer, which means the target value is not in the array.

By continuously updating the left and right pointers, the Binary Search algorithm effectively halves the search space at each step, making it a very efficient search algorithm with a time complexity of O(log n).