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Which of the two functions below has the smallest minimum y-value?f(x) = 4(x - 6)4 + 1g(x) = 2x3 + 28A.The extreme minimum y-value for f(x) and g(x) is −∞−∞B.g(x)C.f(x)D.There is not enough information to determineSUBMITarrow_backPREVIOUS

Question

Which of the two functions below has the smallest minimum y-value?f(x) = 4(x - 6)4 + 1g(x) = 2x3 + 28A.The extreme minimum y-value for f(x) and g(x) is −∞−∞B.g(x)C.f(x)D.There is not enough information to determineSUBMITarrow_backPREVIOUS

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Solution

To find the minimum y-value of the functions, we need to understand the nature of the functions first.

f(x) = 4(x - 6)^4 + 1 is a quartic function, which means it's a polynomial of degree 4. The leading coefficient is positive, so the function opens upwards. This means it has a minimum value. The minimum value occurs at the vertex of the function, which in this case is (6,1).

g(x) = 2x^3 + 28 is a cubic function, which means it's a polynomial of degree 3. Cubic functions do not have a minimum or maximum value because they extend from negative infinity to positive infinity.

So, the function f(x) has a minimum y-value at (6,1), while g(x) does not have a minimum y-value. Therefore, the answer is C. f(x).

This problem has been solved

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