SELECT round(sum(item_count*order_occurrences)/sum(order_occurrences),1) as meanFROM items_per_order

The sum of items divided by the number of  items is the ..*1 pointA. frequencyB. meanC. medianD. mode

29. What is the result of the following SQL Query? SELECT COUNT(*), AVG(amount) FROM Orders WHERE amount > 200; Number of orders with amount > 200 and the average amount of these orders.Total number of orders and the average amount of all orders.Number of customers with orders > 200 and the average order amount per customer.Total number of orders > 200 and the average number of orders.

In SQL, which aggregate function is used to find the sum of a numeric column?OptionsTOTAL()COUNT()AVERAGE()SUM()

There are a total of 500 orders with one item per order, 1000 orders with two items per order, and 800 orders with three items per order."Example Output:mean2.7ExplanationLet's calculate the arithmetic average:Total items = (1*500) + (2*1000) + (3*800) + (4*1000) = 8900Total orders = 500 + 1000 + 800 + 1000 = 3300Mean = 8900 / 3300 = 2.7The dataset you are querying against may have different input & output - this is just an example!Gimme a Hint12function round(double precision, integer) does not exist (LINE: 1)PostgreSQL 14Run CodeSubmitErrorfunction round(double precision, integer) does not exist (LINE: 1)

Which aggregate function returns the average of values in a numeric column?