What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?A.0.2 mol/kgB.0.5 mol/kgC.2 mol/kgD.5 mol/kgSUBMITarrow_backPREVIOUS
Question
What is the molality of a solution made by dissolving 2 moles of NaOH in 10 kg of water?A.0.2 mol/kgB.0.5 mol/kgC.2 mol/kgD.5 mol/kgSUBMITarrow_backPREVIOUS
Solution
Molality is defined as the number of moles of solute per kilogram of solvent. In this case, the solute is NaOH and the solvent is water.
Given:
- Moles of NaOH (solute) = 2 moles
- Mass of water (solvent) = 10 kg
We can calculate molality (m) using the formula:
m = moles of solute / mass of solvent in kg
Substituting the given values into the formula, we get:
m = 2 moles / 10 kg = 0.2 mol/kg
So, the molality of the solution is 0.2 mol/kg. Therefore, the correct answer is A.0.2 mol/kg.
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