A typical reverse recovery time @ dIF/dt = 25A and 25 degree Celsius for a fast diode VS-70HFL is given as 500 ns and a typical reverse recovered charge is given as 1300 nC. If the off-state reverse voltage in certain application is 540 Volts and the operating frequency is 20kHz. The switching power loss in Watts is given as approximately:
Question
A typical reverse recovery time @ dIF/dt = 25A and 25 degree Celsius for a fast diode VS-70HFL is given as 500 ns and a typical reverse recovered charge is given as 1300 nC. If the off-state reverse voltage in certain application is 540 Volts and the operating frequency is 20kHz. The switching power loss in Watts is given as approximately:
Solution
The switching power loss can be calculated using the formula:
P = Qrr * Vrr * f
where:
- Qrr is the reverse recovery charge (1300 nC or 1.3 x 10^-9 C)
- Vrr is the off-state reverse voltage (540 V)
- f is the frequency (20 kHz or 20 x 10^3 Hz)
Substituting the given values into the formula, we get:
P = 1.3 x 10^-9 C * 540 V * 20 x 10^3 Hz
Solving this gives:
P = 0.01404 W or 14.04 mW
So, the switching power loss is approximately 14.04 mW.
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