A number greater than 32 would require a minimum of how may bits in binary representation? 56410
Question
A number greater than 32 would require a minimum of how may bits in binary representation? 56410
Solution
The question seems to be a bit unclear, but if you're asking about the minimum number of bits required to represent a number greater than 32 in binary, here's how you can calculate it:
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First, find the next power of 2 that is greater than 32. That would be 64 (2^6).
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The power to which 2 is raised (in this case, 6) is the minimum number of bits required to represent numbers up to that power of 2. However, since we want to represent a number greater than 32, we need an additional bit.
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Therefore, a number greater than 32 would require a minimum of 7 bits in binary representation.
If you're asking about the binary representation of the number 56410, here's how you can calculate it:
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Convert the decimal number to binary. The binary representation of 56410 is 1101110000011010.
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Count the number of bits in the binary representation. In this case, the binary representation of 56410 has 16 bits.
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