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A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?A.

Question

A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?A.

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Solution

Step 1: Calculate the total time the watch has been running

From noon on Monday to 2 p.m. on the following Monday is a total of 7 days and 2 hours, or 170 hours.

Step 2: Calculate the total gain of the watch

The watch was 2 minutes slow at the start and 4 minutes and 48 seconds fast at the end. This is a total gain of 2 minutes + 4 minutes 48 seconds = 6 minutes 48 seconds, or 408 seconds.

Step 3: Calculate the rate of gain

The watch gains 408 seconds in 170 hours, so the rate of gain is 408 seconds / 170 hours = 2.4 seconds per hour.

Step 4: Calculate when the watch showed the correct time

The watch was 2 minutes (or 120 seconds) slow at noon on Monday. At a rate of gain of 2.4 seconds per hour, it would take 120 seconds / 2.4 seconds per hour = 50 hours for the watch to show the correct time.

So, the watch showed the correct time 50 hours after noon on Monday, which is 2 p.m. on Wednesday.

This problem has been solved

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