A 7.80 g bullet moving at 575 m/s strikes the hand of a superhero, causing the hand tomove 5.50 cm in the direction of the bullet’s velocity before stopping.(a) Use work and energy considerations to find the average force that stops the bullet.(b) Assuming the force is constant, determine how much time elapses between themoment the bullet strikes the hand and the moment it stops moving.

(a) To find the average force that stops the bullet, we can use the work-energy principle. The work done on an object is equal to the change in its kinetic energy.

The initial kinetic energy of the bullet can be calculated using the formula: KE_initial = (1/2) * mass * velocity^2

Substituting the given values, we have: KE_initial = (1/2) * 7.80 g * (575 m/s)^2

Next, we need to find the final kinetic energy of the bullet. Since the bullet comes to a stop, its final kinetic energy is zero.

Using the work-energy principle, we can write: Work_done = KE_final - KE_initial

Since the work done is equal to the average force multiplied by the displacement, we have: Average_force * displacement = KE_final - KE_initial

Substituting the given displacement of 5.50 cm (converted to meters) and solving for the average force, we get: Average_force = (KE_final - KE_initial) / displacement

(b) To determine the time elapsed between the moment the bullet strikes the hand and the moment it stops moving, we can use the equation of motion:

v_final = v_initial + (average_force / mass) * time

Since the final velocity is zero when the bullet stops moving, we can rearrange the equation to solve for time:

time = -v_initial / (average_force / mass)

Substituting the given initial velocity and the average force calculated in part (a), we can find the time elapsed.