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The megagametophyte of angiosperms is comprised of 7 cells, but 8 nuclei. How many rounds of mitotic cell division does the megaspore undergo to produce the megagametophyte?

Question

The megagametophyte of angiosperms is comprised of 7 cells, but 8 nuclei. How many rounds of mitotic cell division does the megaspore undergo to produce the megagametophyte?

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Solution

The megaspore of angiosperms undergoes three rounds of mitotic cell division to produce the megagametophyte. Here's how:

  1. The first round of mitotic division: The megaspore divides to form two cells. Each cell contains one nucleus.

  2. The second round of mitotic division: Each of the two cells divides again, resulting in a total of four cells. Each cell contains one nucleus.

  3. The third round of mitotic division: One of the four cells divides again, resulting in a total of five cells. However, one of these cells, called the central cell, undergoes a second division without cytokinesis (the process that usually separates one cell into two during cell division). This results in the central cell containing two nuclei, while the other cells each contain one nucleus.

So, after three rounds of mitotic division, the megagametophyte of angiosperms is comprised of seven cells (four from the second round of division, two from the third round, and the central cell) and eight nuclei (one in each of the five cells from the third round of division, and three in the central cell).

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